Math Problem Statement

Show that that the number 3^(2,012)+3^(2,009) is divisble by 12

Solution

To show that 32012+320093^{2012} + 3^{2009} is divisible by 12, we will break the proof into steps, examining divisibility by both 3 and 4 (since 12=3×412 = 3 \times 4).

Step 1: Check divisibility by 3

We start by checking the expression 32012+320093^{2012} + 3^{2009} modulo 3. Since powers of 3 are clearly divisible by 3, both 320123^{2012} and 320093^{2009} are divisible by 3. Therefore: 32012+320090+00(mod3)3^{2012} + 3^{2009} \equiv 0 + 0 \equiv 0 \pmod{3} Thus, 32012+320093^{2012} + 3^{2009} is divisible by 3.

Step 2: Check divisibility by 4

Now, we need to check if 32012+320093^{2012} + 3^{2009} is divisible by 4. To do this, we first observe the behavior of powers of 3 modulo 4: 313(mod4),321(mod4),333(mod4),341(mod4)3^1 \equiv 3 \pmod{4}, \quad 3^2 \equiv 1 \pmod{4}, \quad 3^3 \equiv 3 \pmod{4}, \quad 3^4 \equiv 1 \pmod{4} So, the powers of 3 modulo 4 alternate between 3 and 1. Specifically:

  • If the exponent is odd, 3n3(mod4)3^n \equiv 3 \pmod{4}.
  • If the exponent is even, 3n1(mod4)3^n \equiv 1 \pmod{4}.

Now, check the two terms in the expression:

  • 320123^{2012}: Since 2012 is even, 320121(mod4)3^{2012} \equiv 1 \pmod{4}.
  • 320093^{2009}: Since 2009 is odd, 320093(mod4)3^{2009} \equiv 3 \pmod{4}.

Thus: 32012+320091+340(mod4)3^{2012} + 3^{2009} \equiv 1 + 3 \equiv 4 \equiv 0 \pmod{4} Therefore, 32012+320093^{2012} + 3^{2009} is divisible by 4.

Step 3: Conclusion

Since 32012+320093^{2012} + 3^{2009} is divisible by both 3 and 4, it is divisible by lcm(3,4)=12\text{lcm}(3, 4) = 12.

Thus, we have shown that 32012+320093^{2012} + 3^{2009} is divisible by 12.

Would you like further details on any part of this explanation?

Here are some related questions you might find interesting:

  1. How do we determine the pattern of powers of 3 modulo different numbers?
  2. Can this method be used to prove divisibility by other numbers?
  3. What are some examples of numbers divisible by both 3 and 4?
  4. How would the process differ for other bases, such as 2 or 5?
  5. How can modular arithmetic help solve other divisibility problems?

Tip: Modular arithmetic is a powerful tool for checking divisibility by specific numbers. It's helpful to identify periodic patterns in powers of numbers modulo smaller divisors like 3, 4, and 5.

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Math Problem Analysis

Mathematical Concepts

Modular Arithmetic
Number Theory
Divisibility Rules

Formulas

Modular equivalence: a ≡ b (mod n)
Powers of numbers modulo n

Theorems

Divisibility Theorem
LCM and GCD properties

Suitable Grade Level

Grades 9-12