Math Problem Statement
Show that that the number 3^(2,012)+3^(2,009) is divisble by 12
Solution
To show that is divisible by 12, we will break the proof into steps, examining divisibility by both 3 and 4 (since ).
Step 1: Check divisibility by 3
We start by checking the expression modulo 3. Since powers of 3 are clearly divisible by 3, both and are divisible by 3. Therefore: Thus, is divisible by 3.
Step 2: Check divisibility by 4
Now, we need to check if is divisible by 4. To do this, we first observe the behavior of powers of 3 modulo 4: So, the powers of 3 modulo 4 alternate between 3 and 1. Specifically:
- If the exponent is odd, .
- If the exponent is even, .
Now, check the two terms in the expression:
- : Since 2012 is even, .
- : Since 2009 is odd, .
Thus: Therefore, is divisible by 4.
Step 3: Conclusion
Since is divisible by both 3 and 4, it is divisible by .
Thus, we have shown that is divisible by 12.
Would you like further details on any part of this explanation?
Here are some related questions you might find interesting:
- How do we determine the pattern of powers of 3 modulo different numbers?
- Can this method be used to prove divisibility by other numbers?
- What are some examples of numbers divisible by both 3 and 4?
- How would the process differ for other bases, such as 2 or 5?
- How can modular arithmetic help solve other divisibility problems?
Tip: Modular arithmetic is a powerful tool for checking divisibility by specific numbers. It's helpful to identify periodic patterns in powers of numbers modulo smaller divisors like 3, 4, and 5.
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Math Problem Analysis
Mathematical Concepts
Modular Arithmetic
Number Theory
Divisibility Rules
Formulas
Modular equivalence: a ≡ b (mod n)
Powers of numbers modulo n
Theorems
Divisibility Theorem
LCM and GCD properties
Suitable Grade Level
Grades 9-12